3 ms·
Which means that many of Hamiltonian paths are strictly dominated than others, so you don’t have to evaluate them at all. Same as in sorting you don’t have to e
by whatever1 5y ago
Which means that many of Hamiltonian paths are strictly dominated than others, so you don’t have to evaluate them at all. Same as in sorting you don’t have to evaluate all of the possible pairs.
I did not imply that all information is useful. I proposed that probably there is a lower bound of information that you definitely need to find the optimal solution to the tsp.