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If blocks in the "miner" chain break the rules of the "dev" chain, then no flag is required. You'll automatically stick with the chain that contains valid block
by jstanley 5y ago
If blocks in the "miner" chain break the rules of the "dev" chain, then no flag is required. You'll automatically stick with the chain that contains valid blocks, as determined by the implementation that you're running.
- brighton36 5y agoEventually the us government will decide what codebase is valid. And exchanges will immediately switch to that codebase. Probably that codebase will support kyc and whitelist/blacklist functions. Bitcoin is fiat. It doesn't have 79 protons in it's nucleus.