> Your Law of Optimization reminds me of the (often popularly ignored) denominator in the famous e = m c^2 equation. > I believe the full version has a (1 - (v

> Your Law of Optimization reminds me of the (often popularly ignored) denominator in the famous e = m c^2 equation. > I believe the full version has a (1 - (v/c)^2) denominator on the right side …. I think the question is what you mean by `m`. If it's inertial mass, then I believe no correction is necessary. The point is that the inertial mass `m` is the rest mass `m_0` divided by `\sqrt{1 - (v/c)^2}`, as you say.