3 ms·
It's not a leaky abstraction, because it doesn't make any promises about performance. If you still call it a "leaky abstraction" then _every_ abstraction is lea
by valenterry 5y ago
It's not a leaky abstraction, because it doesn't make any promises about performance. If you still call it a "leaky abstraction" then _every_ abstraction is leaky and we can simply alias "leaky abstraction" to "abstraction" and move on.