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I noticed this too. The example would make more sense if the rules were changed so that the pot is multiplied, say by 2. Then the optimal case is both put in $5
by Raphael 15y ago
I noticed this too. The example would make more sense if the rules were changed so that the pot is multiplied, say by 2. Then the optimal case is both put in $5 and end up with $10.
- repsilat 15y agoIt has to be multiplied by less than two - if it's multiplied by two or more, putting money into the pot is always worthwhile (or at least break-even), no matter how much the other player puts in.