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Thank you! The Bose Sounddock for iPod that I found in a recycling bin uses a dual +/- 18V power supply, and I was wondering how to power it from batteries. Tha
by peterburkimsher 5y ago
Thank you! The Bose Sounddock for iPod that I found in a recycling bin uses a dual +/- 18V power supply, and I was wondering how to power it from batteries. That link taught me that the extra voltage headroom may not be required, it might run on 12V, and it would in theory be possible to build a +/- dual voltage circuit. Now I just have to decide whether it's worth building that and learning more about power electronics, or buying a new speaker and having a somewhat safer device.
- analog31 5y agoHere's another take on a similar theme. I've built a few of these: https://www.maximintegrated.com/en/design/technical-documents/app-notes/4/4434.html https://www.maximintegrated.com/en/design/technical-document... In my case, I was looking for a way to get decent analog power from a USB port for a non audio related project, but a LiPo battery would present a similar challenge.
- kevin_thibedeau 5y agoCharge pump ICs can't supply high currents on their own and their output is unregulated. It's unlikely you would get acceptable results from the speaker if you followed this blog for guidance.
- nitrogen 5y agoWould four 9V batteries in series with ground drawn from the middle supply enough current?
- tuatoru 5y agoEnough current for what? Power = voltage x current = (voltage) squared / resistance. The little rectangular 9V batteries have very high internal resistance as well as low energy capacity. The nominal 9V can easily fall below 6V with heavy loads. If you only need 1 watt (times 2 for stereo), loud enough for average rooms with speakers of reasonable efficiency, then one 9V battery would be enough. It wouldn't last long though. With two in series you can go louder, provided the amplifier is rated for the higher voltage. Remember to put fuses in your power leads (except the ground return). Good quality batteries can get hot trying to power a short circuit.