Yeah, noexcept(true) is identical to wrapping the function with a try-catch construct in which the catch clause simply calls std::terminate(). Your godbolt exam

Yeah, noexcept(true) is identical to wrapping the function with a try-catch construct in which the catch clause simply calls std::terminate(). Your godbolt example doesn't include the definition of n() so it doesn't show that. Adding noexcept(true) has a cost (because it's a kind of exception handling) but also allows the compiler to optimize out some of that cost under some circumstances. Nevertheless, an example that demonstrates the exception path doesn't say much about the "zero-cost" non-exception path. In C++ exception handling is expensive. Outside of actually directly handling exceptions they have zero cost. There are no generated instructions. They do not consume cache. They do not hinder further optimizations.