In https://docs.python.org/3.11/whatsnew/3.11.html https://docs.python.org/3.11/whatsnew/3.11.html : > A new function operator.call has been added, such that

In https://docs.python.org/3.11/whatsnew/3.11.html https://docs.python.org/3.11/whatsnew/3.11.html : > A new function operator.call has been added, such that operator.call(obj, *args, **kwargs) == obj(*args, **kwargs). Isn't this the same as the old apply function? https://docs.python.org/2/library/functions.html#apply https://docs.python.org/2/library/functions.html#apply Ah, it was discussed: https://bugs.python.org/issue44019#msg400821 https://bugs.python.org/issue44019#msg400821 > Python2's apply has different semantics: it takes non-unpacked arguments, i.e. def apply(f, args, kwargs={}): return f(*args, **kwargs) > rather than def call(f, *args, **kwargs): return f(*args, **kwargs)