3 ms·
You could argue: If it's 1/10th the size, then it's about 1/3 the length and width. So, average distance (if you pick two points uniformly randomly) will also b
by FabHK 5y ago
You could argue: If it's 1/10th the size, then it's about 1/3 the length and width. So, average distance (if you pick two points uniformly randomly) will also be around 1/3. By this logic, it should be around 1000 EUR.