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NB: Post author here. This is great! So fun...will have to use in the future...

• pdpi 5y ago
  While I have your attention... > For the median and average to be equal, the points less than the median and greater than the median must have the same distribution (i.e., there must be the same number of points that are somewhat larger and somewhat smaller and much larger and much smaller). [0, 2, 5, 9, 9] has both median and mean = 5, but the two sides don't really have the same distribution.
  • djk447 5y ago
    Totally true...thoughts on how I could rephrase? I guess it's more the "weight" of points greater than and less than the median should be the same, so symmetric distributions definitely have it, asymmetric may or may not. Definitely open to revising...
    • pdpi 5y ago
      > symmetric distributions definitely have it, asymmetric may or may not Doesn't have to be any more complicated than that. It's more a curio than an important point anyway :)