3 ms·
This is only true if your stages don't have arguments: with a | b(something) | c | d, `something` is now evaluated before b(something)
by fiddlerwoaroof 5y ago
This is only true if your stages don't have arguments: with a | b(something) | c | d, `something` is now evaluated before b(something)
- grapist420 5y agotrue, although argument evaluation order in a(x,b(y,c(d),z),w) is already somewhat hard to rely on