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As a fellow student of "why is this named that, what does this name mean" I have found that asking about counterfactuals is rarely satisfying. Naming stuff is h
by burnished 5y ago
As a fellow student of "why is this named that, what does this name mean" I have found that asking about counterfactuals is rarely satisfying. Naming stuff is hard and the question assumed a level of intent that I think is rarely present. Asking "how did this thing get named that" works out better, cause it seems that occasionally gets written down.
- jstanley 5y agoMy point was that it seems more likely that size_t was created to represent sizes than to represent indexes. I don't disagree that size_t is an appropriate type for indexes, but I don't think indexes are literally the reason it was created.
- tialaramex 5y agoIt's named for sizeof, a C operator which returns a positive integer but annoyingly the core C language itself doesn't define what the type of that integer is, the standard library does though, naming it size_t Now, sizeof does measure the size of things, but, one of the obvious sizes you can measure is an array†, and that's definitely also the maximum index value for the array, so I do think it's fair to say that's (part of) literally why size_t exists. † One of C's treacherous footguns. In the scope where the array was defined it's an array, and sizeof(array) tells you how big that array is. But, passed as a parameter it becomes a pointer and sizeof(resulting_pointer) is the size of the pointer, not the array :(
- _kst_ 5y agoThe core language says that the result of sizeof is size_t, defined in <stddef.h> (and other headers). size_t is a typedef (alias) for an implementation-defined unsigned integer type. It could have been worded differently with the same meaning. For example, the core language (section 6 of the standard) could have said that sizeof yields a result of an implementation-defined unsigned integer type without referring to "size_t". The library section (section 7) already says that size_t "is the unsigned integer type of the result of the sizeof operator". Personally I think that referring to size_t in the language section adds clarity, even if it's slightly redundant. In a given implementation, a compiler might arrange for sizeof to yield a result of type unsigned long, for example. The corresponding <stddef.h> header must then define size_t as unsigned long for the implementation to be correct.
- Thorrez 5y ago>Now, sizeof does measure the size of things, but, one of the obvious sizes you can measure is an array†, and that's definitely also the maximum index value for the array Make sure to be careful and realize that sizeof my_array returns the number of bytes that my_array uses, not the number of elements. An array of 10 ints likely has sizeof == 40, while indexing past 9 would be undefined behavior.
- tialaramex 5y agoExcellent point, that largely contradicts my earlier position in fact. I was thinking of an array of chars and should have considered that's only a special case.
- burnished 5y agoWell, my point is that "more likely" and "more reasonable" are rarely reasons why things were done in the first place so using the benefit of hindsight to try and suss out cause and effect will frequently lead you to plausible but incorrect answers (specifically for the history and naming of things). Then again, being wrong about something seems faster than asking a question, and this little thread has already unearthed interesting answers, so maybe you have the right of it!
- Thorrez 5y agoI agree and disagree. Yes it was created for size. But when indexing std::vector you can index up to the size, and thus should use the same type for both.