The Newton iteration is nicer for the inverse square root than for the square root. You can refine an initial approximation for `1 / sqrt(x)`, and multiply the

The Newton iteration is nicer for the inverse square root than for the square root. You can refine an initial approximation for `1 / sqrt(x)`, and multiply the result by `x` to compute an approximation of `sqrt(x)`. This less direct approach only needs FP multiplications and additions (and the initial approximation).