3 ms·
Ok now we’re getting somewhere. So the equation shows that as d goes up, C goes down. But as d goes up the breakdown voltage also increases so my question is
by mrfusion 5y ago
Ok now we’re getting somewhere.
So the equation shows that as d goes up, C goes down.
But as d goes up the breakdown voltage also increases so my question is why can’t we force more voltage on there.
- goldenkey 5y agoYou can but eventually the voltage gets so high that the resistance of the air isn't enough to prevent a short via a discharge. And in a vacuum, the resistance is even less. One would have to keep the capacitor in a super resistant gas or fluid to prevent a short.
- mrfusion 5y agoYeah that’s what I’m trying to figure out. Maybe energy storage wise it’s worth encasing it in a large amount of high insulator. I’m curious to run those numbers but I’m not quite sure how to approach it.