3 ms·

As opposed to what?

by teilo 5y ago

As opposed to what?

drran 5y ago
As opposed to one of "tired light" models. Light is not immortal, so it loses some energy with time. E.g. gravitational noise can affect photon energy, or photon can lose some energy to medium due to friction, or photon can lose some energy because of truncation of ideal sinusoidal wave at Planck scale, or speed of light is a bit slower than c (because light arrived 16 seconds later than gravitational waves, when gravitational waves were discovered), thus photon is not frozen in time and expands at very slow rate.
- zozbot234 5y ago
  The standard argument against 'tired light' is that it should lead to scattering of light from more distant objects, but this has not been observed in the data.
  - sahil50 5y ago
    The standard argument is a straw man argument. Tired light is not photons getting scattered, and is not photons bumping into stray electrons. Tired light is because there is a cost to traveling through spacetime. The photon is warping the shape of all the universe mass around it. The photon is doing work.
  - drran 5y ago
    The intensity of scattering is proportional to loss of energy. It is impossible to detect such low scattering level in our visible Universe because it is full of gasses and dust, which created many many orders of magnitude stronger scattering, which is still hard to notice except for very bright objects near to dense clouds of dust. It's not possible to confirm or disapprove this argument yet. Moreover, if we are talking about friction and medium (the Ether), then it was predicted long time ago[1], that discussion will be resolved in favor of Ether when Higgs field will be discovered, because Higgs field must be present everywhere, like Ether, and because medium is required for transverse waves to propagate. Discovery of Higgs boson and Higgs field was announced in 2012, so discussion is resolved, but we still call the medium as (physical, quantum) vacuum, like we still call atom as atom («unbreakable») after breaking it, or we use «-» for presence of electrons instead of absence of electrons. (non-native speaker) [1]: https://physicstoday.scitation.org/doi/10.1063/1.882562 https://physicstoday.scitation.org/doi/10.1063/1.882562
sahil50 5y ago
Photon hubbling, tired light. The photon is doing work as it moves through spacetime. Modeled as E_t / E_0 = e^(-Ht), where H is Hubble's constant, and t is time of travel.

As opposed to what?

by teilo 5y ago

As opposed to what?

As opposed to one of "tired light" models. Light is not immortal, so it loses some energy with time. E.g. gravitational noise can affect photon energy, or photon can lose some energy to medium due to friction, or photon can lose some energy because of truncation of ideal sinusoidal wave at Planck scale, or speed of light is a bit slower than c (because light arrived 16 seconds later than gravitational waves, when gravitational waves were discovered), thus photon is not frozen in time and expands at very slow rate.

zozbot234 5y ago
The standard argument against 'tired light' is that it should lead to scattering of light from more distant objects, but this has not been observed in the data.
- sahil50 5y ago
  The standard argument is a straw man argument. Tired light is not photons getting scattered, and is not photons bumping into stray electrons. Tired light is because there is a cost to traveling through spacetime. The photon is warping the shape of all the universe mass around it. The photon is doing work.
- drran 5y ago
  The intensity of scattering is proportional to loss of energy. It is impossible to detect such low scattering level in our visible Universe because it is full of gasses and dust, which created many many orders of magnitude stronger scattering, which is still hard to notice except for very bright objects near to dense clouds of dust. It's not possible to confirm or disapprove this argument yet. Moreover, if we are talking about friction and medium (the Ether), then it was predicted long time ago[1], that discussion will be resolved in favor of Ether when Higgs field will be discovered, because Higgs field must be present everywhere, like Ether, and because medium is required for transverse waves to propagate. Discovery of Higgs boson and Higgs field was announced in 2012, so discussion is resolved, but we still call the medium as (physical, quantum) vacuum, like we still call atom as atom («unbreakable») after breaking it, or we use «-» for presence of electrons instead of absence of electrons. (non-native speaker) [1]: https://physicstoday.scitation.org/doi/10.1063/1.882562 https://physicstoday.scitation.org/doi/10.1063/1.882562

sahil50 5y ago

Photon hubbling, tired light. The photon is doing work as it moves through spacetime. Modeled as E_t / E_0 = e^(-Ht), where H is Hubble's constant, and t is time of travel.