3 ms·

No it's not. In the first line, it's in [0], in the second line, it's in [1], in the third line, it's in [2]. You have to scan through to find where the '0' app

• tlrobinson 15y ago
  True, but it's O(log N) rather than O(N) to determine length. BTW I'm not sure if it was clear or not but those are bits in my diagram, not bytes/characters. The "x"s are the bits of the length field, not the characters of the string.
  • daemin 15y ago
    But you could just as easily set aside the first 4 bytes of a string to be the length and then it would be O(1). But does that really matter when you're doing operations on the string that iterate over the whole string anyway? Since iterating the whole string is O(n) anyway, you're not really gaining anything.
    • fuzzix 15y ago
      Operations to return string length or return characters from the end of the string become far less expensive. You also have a fair idea of a reasonable sized buffer to move in duplication operations, avoiding single character move loops.