5 ms·

Watts = Volts * Amps Any reason you've defined it as: (Amps * Seconds * Volts) / (Amps * Seconds) * (Amps * Seconds * Seconds) ? Fairly sure but not positive

• FabHK 5y ago
  ha, you're right, the Ampere is the SI base unit for purposes of definition, but the Coulomb is arguably the conceptually simpler one... (though Volt is definitely derived). So, in terms of "intuition" (left) and SI base units (right) you have: Watt = J s^-1 = N m s^-1 = kg m^2 s^-3 Volt = J C^-1 = N m A^-1 s^-1 = kg m^2 s^-3 A^-1 Ampere = C s^-1 = A