4 ms·
The thingis exactly that in the B-T paradox you are NOT “cutting”, you are “choosing” non-measurable subsets and reorganizing them. Thus, the operation of “cutt
by pfortuny 5y ago
The thingis exactly that in the B-T paradox you are NOT “cutting”, you are “choosing” non-measurable subsets and reorganizing them. Thus, the operation of “cutting” is not taking place (there is no continuous function whose zeros gives you any of the subsets).