8 ms·
there are many other high cost cities in the world and yet only american liberal ones are in a state of decay and allow homelessness and crime
by ffggvv 5y ago
there are many other high cost cities in the world and yet only american liberal ones are in a state of decay and allow homelessness and crime
- vinay427 5y agoHonest question: Are you claiming that "liberal" has something to do with it? If not, feel free to ignore the rest of this. If so, maybe you can elaborate on what you mean. Are there non-liberal high-cost cities in the US in a better state? Furthermore, it's worth noting that the other high-cost cities worldwide almost universally seem to have more left-leaning (or US liberal) policies on most issues than most high-cost cities in the US. I'm not sure I see the connection between the political alignment and the state of decay, homelessness, and crime in high-cost cities.
- ffggvv 5y agohttps://www.coalitionforthehomeless.org/wp-content/uploads/2020/03/2-1024x699.png https://www.coalitionforthehomeless.org/wp-content/uploads/2... Look at that graph and then ask yourself what changed in 2013. Hint, 1994-2001 they had a republican mayor. 2002-2013 they had a moderate republican who turned into a moderate democrat. And 2014 - now they've had a radical progressive.
- objectivetruth 5y agoThis would make sense if "number of homeless people sleeping in a registered shelter" was in any way a useful statistic. Without a denominator, such as number of available shelter beds, and other data such as where are the shelters in relation to clusters of homeless people... it can tell a lot of different stories. There are millions of variables that inform "the homeless problem" and isolating a pretty minor one -- political affiliation of a single politician in the nation's largest city, overseen by both state and federal governments -- just strikes me as really simplistic.