3 ms·
\* (backslash asterisk) will escape the asterisk. >Also, it has an implicit constructor from `const std::string` and `const char *` allowing you you define a s
by Arnavion 5y ago
\* (backslash asterisk) will escape the asterisk.
>Also, it has an implicit constructor from `const std::string` and `const char *` allowing you you define a single function like `Thing ParseThing(std::string_view line)` and accept `char *` and `std::string` as an input.