3 ms·
Yes. The sign bit is totally independent of the value being encoded, whether that’s a number, q/sNaN, or infinity. Nitpick: we are not flipping the sign bit,
by MontyCarloHall 5y ago
Yes.
The sign bit is totally independent of the value being encoded, whether that’s a number, q/sNaN, or infinity.
Nitpick: we are not flipping the sign bit, but rather setting it to 0.