2 ms·
So there is no change in visible behavior, it is just an implementation detail.
by AshamedCaptain 5y ago
So there is no change in visible behavior, it is just an implementation detail.
- nyrikki 5y agoA very important implementation detail if you are digging into the kernel due to performance problems like in the OP. But yes, in the naive user perspective case the contract hasn't been violated.