4 ms·
log(5x) = log(5) + log(x) log(x/5) = -log(5) + log(x) So the difference is just a sign change on a log scale. And it's natural to use a log scale when wo
by MichaelBurge 5y ago
log(5x) = log(5) + log(x)
log(x/5) = -log(5) + log(x)
So the difference is just a sign change on a log scale. And it's natural to use a log scale when working with percentage changes.
- rusk 5y agoNatural for who? Perhaps better expressed as “5 fold”.