> C++ integers are more like Z/nZ This is an widely-held misconception, but C++ signed integers are _nothing_ like Z/nZ. Unsigned integers are (except for divi

> C++ integers are more like Z/nZ This is an widely-held misconception, but C++ signed integers are _nothing_ like Z/nZ. Unsigned integers are (except for division), and machine arithmetic often is, but in the C++ abstract machine, signed overflow is undefined behavior.