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Honestly missed this. Is that security-through-obscurity? If the model and weights for the second hash function became public, then we could still construct a
by blintz 5y ago
Honestly missed this.
Is that security-through-obscurity? If the model and weights for the second hash function became public, then we could still construct a collision on both functions, right?
- shuckles 5y agoIt’s not security through obscurity. The implementation is not necessarily a secret; it’s the model configuration which can only be differentiated if known. Since part of the threat is adversarial embeddings, it’s perfectly fine to assume you can keep a private model confidential that adversaries can’t differentiate.