3 ms·
It's not, a 16bit LE value at address 0 will have the low byte at address 0 and the high byte at 1. Unless I misunderstood what you meant with "little end"? (Bu
by anyfoo 5y ago
It's not, a 16bit LE value at address 0 will have the low byte at address 0 and the high byte at 1. Unless I misunderstood what you meant with "little end"? (But then there is still room for confusion in that term, apparently.)
- kevin_thibedeau 5y agoThe little end is always at a lower address. It doesn't matter which way you draw the number line.
- anyfoo 5y agoAh, I see what you mean now. We are in agreement after all.