3 ms·
No, it's not. The method described by ARM is functionally identical, so it is equally biased as the method described in the blog post here.
by pwuille 5y ago
No, it's not. The method described by ARM is functionally identical, so it is equally biased as the method described in the blog post here.
- kwillets 5y agoI see, this is one of several posts on this topic. There is a link near the end to the unbiased method, which is more original, but as you note fixed-point multiplication is not new.