3 ms·
Yes. Thrust is related to momentum while power to energy. So if you double the exhaust velocity, you double the thrust but quadruple the power needed. P =
by Gravityloss 5y ago
Yes. Thrust is related to momentum while power to energy. So if you double the exhaust velocity, you double the thrust but quadruple the power needed.
P = 0.5 * mdot * v_ex^2
T = mdot * v_ex
A normal ion thruster might have ISP 4000 or 40 km/s exhaust velocity.
From the rocket equation, if our mission requires 10 km/s delta vee, mass ratio is exp(10/40)=1.28. So out of every 1280 kg, 280 kg is propellant.
If we have mass flow of 0.1 gram per second, thrust is 40000 m/s * 0.0001 kg/s = 4 N and power is 80 kW.
Acceleration is about 0.27 km/s per day. Not so good for humans through Van Allen belts. But fine for deep space propulsion.
80 kW of solar cells with 200 W/kg weight efficiency would weigh 400 kg. This is ISS level power.
So the spacecraft might have 280 kg of propellant, 400 kg of solar arrays, 600 kg of useful things.
- sdenton4 5y agoYeah, so my question comes down to 'how much can we play around with weight efficiency?' For example, maybe I can drop a lot of solar cells in exchange for a small battery or capacitor capable of providing the needed power for the higher exhaust velocity, but in bursts. Then we change the firing pattern from a continuous burn to alternating between burning and recharging the batteries, and save a lot of solar panel weight. [on edit: the weight efficiency of the solar panels will also depend on where you are in the solar system...]
- Gravityloss 5y agoYou can never increase efficiency by storing the energy. You will just have additional battery mass. It can not help.