2 ms·

You are; coney in English generally has a long e sound at the end (like saying the letter 'e'), not a long a sound (like saying the letter 'a'), so it wouldn't

You are; coney in English generally has a long e sound at the end (like saying the letter 'e'), not a long a sound (like saying the letter 'a'), so it wouldn't be the same or rhyme with the first two syllables of conejo (which has the long a sound in the second syllable). Tangent, but in line with what others have commented, American English tends to pronounce the first syllable with a long o (like saying the letter 'o'), whereas British tends to pronounce it with a long oo sound (like the vowel sound in the the word 'food'). I've never heard it pronounced with a short 'u' sound (an 'uh' sound), but others intimated they either have, or have heard it pronounced close to it, which is interesting.

tuukkah 5y ago
> conejo (which has the long a sound in the second syllable). The Spanish word is pronounced more like "koh-neh-hoh" (or [ko'neho] in IPA), no "long a" ([ei] in IPA) there. The English "long vowels" (diphthongs really: a combination of two vowel sounds) would be written with two letters in Spanish (and IPA).
- thaumasiotes 5y ago
  > The English "long vowels" (diphthongs really: a combination of two vowel sounds) would be written with two letters in Spanish (and IPA). Three out of five are diphthongs. "Long E" is /i/. "Long u" is /u/.
  - tuukkah 5y ago
    Good clarification. Depending on the variant of English, "long e", "long u" and "long a" may or may not sound like diphthongs. They can be analysed as /ij/ and /uw/. Wikipedia puts them under "potential diphthongs". https://en.wikipedia.org/wiki/Diphthong#English https://en.wikipedia.org/wiki/Diphthong#English https://en.wikipedia.org/wiki/English_phonology#Vowels https://en.wikipedia.org/wiki/English_phonology#Vowels