3 ms·
> Language of percentages is not supposed to be used this way. Umm, it is though? Given the probability (or risk) P(unvac) of an unvaccinated person to get in
by dagsdgfhdgdj 5y ago
> Language of percentages is not supposed to be used this way.
Umm, it is though?
Given the probability (or risk) P(unvac) of an unvaccinated person to get infected, the probability P(vac) of a vaccinated person is 90% lower, or:
P(vac) = (1 - 90%) * P(unvac) = 0.1 * P(unvac)
- effie 5y agoI understand that meaning, but it is very strange and confusing formulation. Just say it's 10x lower.