3 ms·
No. I think your code will be transformed into: const [r1, r2, r3] = await Promise.all(await [ await (async () => { ... }), await (async () =>
by nayuki 5y ago
No. I think your code will be transformed into:
const [r1, r2, r3] = await Promise.all(await [
await (async () => { ... }),
await (async () => { ... }),
await (async () => { ... }),
]);