4 ms·

Nope, printf can print strings without NULL-terminator: printf("%.*s", <int>length, <char*>string);

• OskarS 5y ago
  And the first argument to printf (the format), what kind of string is that? And what kind of string does sprintf() produce?
  • TazeTSchnitzel 5y ago
    sprintf tells you how many characters it has written, so there's no reason you can't use it for non-null-terminated strings.
    • comfydragon 5y ago
      williamvds's point is that the first argument to printf is still itself a null-terminated string, so it's basically turtles all the way down if you're using the C standard library.
      • TazeTSchnitzel 5y ago
        Their comment talked about two things, and the sibling comment addressed the other one.
  • 10000truths 5y ago
    In practice, it is almost always a compile-time-known string. gcc will warn you if it isn't, especially since allowing the use of untrusted input for the format can lead to vulnerabilities: https://en.wikipedia.org/wiki/Uncontrolled_format_string https://en.wikipedia.org/wiki/Uncontrolled_format_string
  • tialaramex 5y ago
    Anywhere that this format is a variable, you probably already screwed up. C allows that, but if I see it that's getting flagged in my review. So long as the format string is a literal you needn't care how it works. Now, one of the places where C makes this nastier than it needed to be is that C built-in types are silly, and so any non-trivial program is using better fundamental types like uint32_t (or the more succinct u32), for which the built-in formatter offers no syntax. So you end up writing format strings like "There are "PRIu32" dogs\n" using macros to bring in the appropriate specifier for your literal. Blergh.