3 ms·
Yeah. More specifically, it just inserts whatever behavior it likes for the undefined scenario, which in this case is "the same behavior as in the defined scena
by dataflow 5y ago
Yeah. More specifically, it just inserts whatever behavior it likes for the undefined scenario, which in this case is "the same behavior as in the defined scenario".
- ddalex 5y agoI am utterly confused. How would the compiler know that has_value() guarantees that the ->label dereferencing work, since this is a bitwise operation ?
- dataflow 5y agoI would imagine has_value is checking to see if a pointer is NULL, and -> is dereferencing that same pointer. When the optimizer sees the two together it realizes the former is useless.