3 ms·
The other way around: It shows that I always exists, independent of the number of observing copies (even if it is 0). Basically: There are only weak pointers an
by Lichtso 5y ago
The other way around: It shows that I always exists, independent of the number of observing copies (even if it is 0). Basically: There are only weak pointers and no strong pointer, yet it never gets deallocated or was ever allocated to begin with.
- Tenoke 5y agoI see. Under something like MUH it wouldn't matter, yes. But then nothing matters under MUH anyway.