3 ms·O(n*1000000) is O(n) isn't it?by chrisseaton 5y agoO(n*1000000) is O(n) isn't it?hosteur 5y agoYesnot2b 5y agoRight, but apparently Hacker News changes a * followed by another * into one *, even though several languages use two asterisks as the exponentiation operator.