4 ms·
Works even if Kopecks are divisible: say the books value is 7.5, Mash must have 0.5 (7.5 - 7) and Misha 6.5 (7.5 - 1), however now when you combine them they su
by haxiomic 5y ago
Works even if Kopecks are divisible: say the books value is 7.5, Mash must have 0.5 (7.5 - 7) and Misha 6.5 (7.5 - 1), however now when you combine them they sum to exactly 7.5 not less than, the only way to arrive at less than is if Masha has 0. So its always exactly 7
- LeifCarrotson 5y ago6.5 plus 0.5 is 7.0, they don't add up to exactly 7.5.
- gabagool 5y ago6.5 + 0.5 is 7.0, not 7.5, so that should be valid. The book's cost can lie anywhere between [7, 8).
- haxiomic 5y agoRight on the original typo, but still not convinced, I’ve rephrased to original to try to be clearer
- thaumasiotes 5y ago> say the books value is 7.5, Mash must have 1.5 (7.5 - 7) and Misha 6.5 (7.5 - 1), however now when you combine them they sum to exactly 7.5 not less than There are several problems with this: - 7.5 - 7 is 0.5, not 1.5 - 1.5 + 6.5 is 8, not 7.5 - 0.5 + 6.5 is still less than 7.5 The problem specifies that 2x - 8 < x. There is no way to constrain this to the specific solution x = 7. Everything would work fine if the book cost -2.6 kopecks.
- haxiomic 5y agoThank you :) I’m being very clueless today
- deleted 5y ago[deleted]