> Solving for φ = 1 + 1/φ and some quadratic formula reveals this as the golden ratio φ = (1 + √5)/2 x = 1 + 1/x x - 1 - 1/x = 0 x^2 - x - 1 = 0 x = 1

> Solving for φ = 1 + 1/φ and some quadratic formula reveals this as the golden ratio φ = (1 + √5)/2 x = 1 + 1/x x - 1 - 1/x = 0 x^2 - x - 1 = 0 x = 1 ± √(1 + 4) ------------ 2