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No. Trig functions can be defined independently of geometry. One way is by considering the differential equation above. Another is through the Taylor expansion
by mnw21cam 5y ago
No. Trig functions can be defined independently of geometry. One way is by considering the differential equation above. Another is through the Taylor expansion of the sin(x), which is periodic as a completely emergent property.
Likewise, it's hard to imagine what would happen to that very famous equation e^iπ + 1 = 0 if π were something different.
- gspr 5y agoI know. But they do also reflect geometry.