2 ms·
> only Erlang gets it right... [ X || X <- Xs, Xs <- Xss] I don't have much experience with Erlang, but that also seems wrong: 1> Xss = [[1]]. [[1]] 2>
by jolmg 5y ago
> only Erlang gets it right... [ X || X <- Xs, Xs <- Xss]
I don't have much experience with Erlang, but that also seems wrong:
1> Xss = [[1]].
[[1]]
2> [ X || X <- Xs, Xs <- Xss].
* 1:13: variable 'Xs' is unbound
3> [ X || Xs <- Xss, X <- Xs].
[1]
- dmitriid 5y agoDamnit. I haven't used Erlang in a long time, but I should've known that. So, no language does it "right".