5 ms·
The methodology is a bit odd. As best as I can tell it looks at the cheapest data plan that offers >500MB. If there's a plan that's $1 more per month but offers
by mjlee 5y ago
The methodology is a bit odd. As best as I can tell it looks at the cheapest data plan that offers >500MB. If there's a plan that's $1 more per month but offers 100GB of data, the price per visit would drop rapidly but this tradeoff wouldn't be reflected in their price.
They say it's "best case" but that appears to be based on the minimum hurdle to get a data plan, rather than the minimum data price.
I think a better measurement would be a range based on a few different price levels (cheapest/most expensive/modal) but I understand that would be much harder to implement.
- viraptor 5y agoI honestly can't tell if the "least expensive plan" combined with "best case scenario" actually means the lowest total price, or least expensive per MB. I agree that it's either odd methodology or odd wording.
- londons_explore 5y agoA more representative figure would be to look at the typical data plans actual citizens of those countries have. Eg. Ask 100 citizens how many gb's they have and how much they pay. Calculate cost per gb for each. Take median.