4 ms·
Wouldn't this logic only apply if the distribution is symmetric? We know it can't be symmetric, because there is a lower bound to how cold it can get, but no up
by cout 5y ago
Wouldn't this logic only apply if the distribution is symmetric? We know it can't be symmetric, because there is a lower bound to how cold it can get, but no upper bound to how hot it can get; the question then whether the asymmetry is significant or whether a symmetric model is close enough.
(To clarify: I'm specifically asking about your use of a binomial distribution, not about the linked paper).
- jfim 5y agoI'd have to think more about it, but assuming a mild skewness in the distribution, it shouldn't matter too much. This is not unlike the Mann–Whitney U test where the sign of the difference matters, not the magnitude of the difference. As for the bounds on the distribution, while it's true that there is an absolute minimum temperature, in practice I don't think a temperature anywhere near it has been reached by natural means on the surface of the Earth.
- deleted 5y ago[deleted]