4 ms·
Thanks for posting the abstract. It's $2^{14}$ leaves in the original LaTeX rather than 214, just in case anyone is confused. (It's also $O(\log_k n)$ = O(log n
by Kuszmaul 5y ago
Thanks for posting the abstract. It's $2^{14}$ leaves in the original LaTeX rather than 214, just in case anyone is confused. (It's also $O(\log_k n)$ = O(log n / log k).)