I just found that boltons supports a mean, in boltons.statsutils.mean . It appears to use the naive summation: >>> import boltons.statsutils >>> data = (1_

I just found that boltons supports a mean, in boltons.statsutils.mean . It appears to use the naive summation: >>> import boltons.statsutils >>> data = (1_000_000_000.1, 1.1) * 50_000 >>> boltons.statsutils.mean(data) 500000000.60091573 >>> sum(data) / len(data) 500000000.60091573