3 ms·
If you are looking for such accuracy (where 50_000_000.00006 is different from 50_000_000.06) then you need a specialised library and do very careful coding. I
by worik 5y ago
If you are looking for such accuracy (where 50_000_000.00006 is different from 50_000_000.06) then you need a specialised library and do very careful coding.
If you are averaging bazillions of numbers and they range from weeny to huge and you thing 50_000_000.000006 != 50_000_000.06 for your purposes then it is hard for me to see that you are doing anything sensible.
This is, except in very specialised cases that I cannot imagine, a non issue.
Just add them up and divide, (and check for overflow, that could ruin your day!)