3 ms·
e^(iτ) = 1, not 0
by SuchAnonMuchWow 5y ago
e^(iτ) = 1, not 0
- susam 5y agoOops! I meant to write e^(iτ) - 1 = 0. I was going back and forth between the various formulations of the identities: e^(iπ) + 1 = 0, e^(iτ) - 1 = 0, e^(iπ) = -1, e^(iτ) = 1. The one involving pi looks more elegant when written in the first manner. The one involving tau looks more elegant when written in the fourth manner. I screwed up this one while going back and forth between these options. I have fixed it now. Thanks for noticing and commenting!
- BlueTemplar 5y agoI don't "get" the first two. e^(iτ/2) = -1 can be translated as "half a full rotation is equivalent to a symmetry" (And a full rotation to identity (for usual objects), but this is kind of obvious...)