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Sort of. Although, for the part that I showed, you don't need the extra assumptions of the implicit function theorem. You only need local invertibility once you
by Tainnor 5y ago
Sort of. Although, for the part that I showed, you don't need the extra assumptions of the implicit function theorem. You only need local invertibility once you actually want to solve the equation. But analysis has been a while for me.
edit: to be more precise, nothing in my answer requires knowing the implicit function theorem. I'm just basically executing the same steps as for the proof of the implicit function theorem, but only for the concrete case of f: R^2 -> R (the implicit function theorem works for any f: R^n -> R^m). If you solve the equation, you need local invertibility (in this concrete example: the partial derivative of f wrt. y needs to be invertible in a neighbourhood of (x, y(x)).
> Another way to see it is to use the total derivative and then (somewhat heuristically) solve it for dy/dx. Mathematicians may yell at you, tho
If you do it properly (i.e. concretely state your assumptions), I don't think mathematicians will yell at you