5 ms·

JS has BigInt now. You can kinda fake BigDecimal with it, but none of the built-in operators will work.

• runarberg 5y ago
  How do you fake BigDecimal with BigInt? My immediate intuition would have a 3-tuple (a, b, c) which would construct the decimal with a representing the numbers before the decimal separator, b the number of zeroes immediately after the decimal separator, and c the numbers after the zeroes. e.g. 1.000054 would be represented as `[1n, 4n, 54n]` and 3.14159 as `[3n, 0n, 14159n]`. Is there a better way?
  • lbussell 5y ago
    What about a 2-tuple with two numbers, one being the BigInt and one being the exponent. So 1.000054 would be (1000054, -6) = 1000054*10^(-6). Yours is probably more space efficient though.
    • wizzwizz4 5y ago
      Yours is more space-efficient for real-world numbers.
    • nine_k 5y ago
      This is basically floating-point. IEEE 754, BTW, allows for 10-based floats, but IDK if anybody uses it.