5 ms·
At 5V and your household needs: 1- refrigerator (400W when it motor is running); 2- vacuum cleaner (1000W when running); 3- TV's/PC's/light-bulbs (around 1000W
by unnouinceput 5y ago
At 5V and your household needs: 1- refrigerator (400W when it motor is running); 2- vacuum cleaner (1000W when running); 3- TV's/PC's/light-bulbs (around 1000W in the evening when all are running at the same time) - all these amounts to at least ~2.5KW power. Now divide that by 5 and you get the intensity at 500A. Do you have any idea how thick the copper would need to be to allow 500A? a full 1cm x 1cm. Any idea how heavy that going to be? Or how expensive? That's why even for 10m distance AC at 220V is better.
- mavhc 5y agoWho's running their vacuum cleaner all evening? My fridge/freezer uses 25 watts average, but the 90% of things I was thinking about was ignoring the heaters and motors, just the lights, computers, speakers etc. Next question, why 5V, when they're talking about 50V. That brings us down to 1/10th the amps. Also this is only inside your house, not for power distribution. Generate your DC power with solar, store it in your car/battery, and power your LED lights, Smart speakers, computers, all the stuff that converts power to DC before it uses it today.
- Ekaros 5y ago25 watts might be average, but what is the peak and consumption during duty cycle?
- unnouinceput 5y agoExactly my point, but @mavhc didn't get it. You vacuum for 10 minutes, but during those 10 minutes if your refrigerator motor is engaged suddenly your standard 3mm copper wires are going to become white hot and melt and you get a nice warming house fire because you didn't thought of the peak intensity. This statement assumes the 5Vcc as house power outlets.