3 ms·
No, it's E=(0.001M)C^2
by varjag 6y ago
No, it's E=(0.001M)C^2
- willis936 6y agoThat is absurd. It is E=MC^2 where M is 0.1% of the total mass of the reactants. 100% of the mass difference is converted into energy.
- varjag 6y agoThe GP was talking in relation to W/Kg, and the output per Kg is definitely not e=mc^2. It helps reading things in the context.
- StavrosK 6y agoYou are correct, though it would help to clarify that you're correcting the GP on the "per kilo" part, and not the "energy" part. I agree, if you're deploying 1 kg of fissile material, only 0.1% of that will be converted to energy. We should talk about energy per mass of fissile material, not energy per mass of "mass difference".