4 ms·
You're not. The FFT is just a particular way of implementing the DFT.
by wnoise 5y ago
You're not. The FFT is just a particular way of implementing the DFT.
- vmilner 5y agoQuite. So I'm puzzled by what mistake the 'skilled programmers' are making, when confusing DFT and FFT. Implementing DFT in quadratic time?